
Integration by parts is your go-to tool for cracking those gnarly integrals that just won’t budge with basic formulas. Honestly, it’s like the reverse gear of the product rule in differentiation. You’ve got a product of two functions staring at you—ugly, messy—and instead of panicking, you flip the script. That’s the trick. It breaks the thing down, swaps one part for its derivative and the other for its integral, and suddenly the problem feels lighter. For Class 12, it’s a game-changer, trust me.
Simple — yeh poora content CBSE syllabus ke hisaab se hi banaya gaya hai. Koi guess nahi, koi random topics nahi. Jo padhna hai, wahi milega.
Here we have provided NCERT Solution for Class 12 गणितI in hindi Language, Just select the chapters below to get solution of the same:
संबंध एवं फलन
प्रतिलोम त्रिकोणमितीय फलन
आव्यूह
सारणिक
सांतत्य तथा अवकलनीयता
अवकलज के अनुप्रयोग
Integration by parts calculus mein ek aisa hathyar hai, jisse hum do functions ke product ka integral nikal sakte hain. Aur suno, iska istemal aksar tab hota hai jab substitution method fail ho jaye — bilkul wahi moment jab lagta hai ki ab kya karein, tabhi ye technique kaam aati hai.
The formula is straightforward: ∫u dv = uv - ∫v du. You’ve got two functions here, u and v. To actually get this, you take the product rule and integrate it. That’s the whole trick behind it.
So, aap U choose karna seekh rahe hain? Simple hai — bas LIATE rule yaad rakhiye. Ye rule batata hai ki kis order me U select karna chahiye: Logarithmic, phir Inverse trigonometric, phir Algebraic, phir Trigonometric, aur last me Exponential. Matlab, jo pehle aata hai list me, usko U bana lijiye. Samjhiye ek example se. Agar integral me ln x dikh raha hai, toh wahan pe U = ln x lena sabse behtar rahega. Aur haan, ye trick kaafi kaam aati hai jab aap complex integrals se jhoojh rahe hote hain.
Here’s the thing — integration by parts is our tool here, and it works like a charm. So we start by picking u = x and dv = e^x dx. That gives us du = dx, and v? Well, that’s just e^x again, nice and clean. Now we plug into the formula: ∫x e^x dx becomes x e^x minus ∫e^x dx. And since ∫e^x dx is e^x, we’re left with x e^x - e^x, plus our constant C. Tidy it up a bit. Factor out the e^x — and you get e^x (x - 1) + C. Done. That’s your answer, plain and simple.
Here’s the solution. Start by picking u = x and dv = sin x dx. That gives you du = dx and v = -cos x. Now plug everything into the integration by parts formula. So you get ∫x sin x dx = x(-cos x) - ∫(-cos x) dx. Clean that up a bit: -x cos x + ∫cos x dx, and the integral of cos x is just sin x. So the final answer is -x cos x + sin x + C. Easy enough once you see the pattern.
NCERT ke Chapter 7, Integrals mein jo examples diye gaye hain, unmein se ek hai ∫x^2 e^x dx. Isse integration by parts se solve karte hain. Chalte hain step-by-step—hum u = x^2 lete hain, aur dv = e^x dx. Phir bas formula apply kar dete hain. Itna hi hai.
A few more to grind through before the big day: ∫e^x cos x dx, ∫x ln x dx, ∫arctan x dx. Just work them out—one by one. You'll feel way more solid by then, no doubt.
Integration by parts samajh liya? Toh aadhe tricky integrals basically solve ho jaate hain—almost like magic. Thoda regular practice, aur NCERT ke examples ko seriously lo—skip mat karna, kyunki wahi base banate hain. Honestly, yeh formula pehle darata hai, but once it clicks? You're golden. Practice hi asli key hai, aur examples ko ignore karna? That's a rookie mistake. Toh haan, consistent effort se, aap confidently exam mein accha score kar sakte hain—bas itna hi.